Write a query to fetch all employees whose salary is greater than 50,000.
Task:
Write a SQL query to fetch all employees whose salary is greater than 50,000.
Step-by-Step Detailed Solution
Step 1: Create the Table (if not already created)
We will create the employees table:
CREATE TABLE employees (
id INT PRIMARY KEY,
name VARCHAR(100),
department VARCHAR(50),
salary DECIMAL(10,2),
hire_date DATE
);
Step 2: Insert Dummy Data
We insert some sample records:
INSERT INTO employees (id, name, department, salary, hire_date) VALUES
(1, 'John Smith', 'HR', 50000.00, '2020-01-15'),
(2, 'Alice Johnson', 'Engineering', 75000.00, '2019-03-22'),
(3, 'Bob Lee', 'Sales', 62000.00, '2021-07-10'),
(4, 'Mary Jane', 'Engineering', 80000.00, '2018-11-05'),
(5, 'Tom Hardy', 'Marketing', 55000.00, '2022-06-01'),
(6, 'Linda Park', 'Support', 48000.00, '2023-01-20');
Step 3: Write the Query
Now, we write a query to fetch employees whose salary is greater than 50,000:
SELECT * FROM employees
WHERE salary > 50000;
Step 4: Output (Result)
After executing the above query, you'll get the following result:
| id | name | department | salary | hire_date |
|---|---|---|---|---|
| 2 | Alice Johnson | Engineering | 75000.00 | 2019-03-22 |
| 3 | Bob Lee | Sales | 62000.00 | 2021-07-10 |
| 4 | Mary Jane | Engineering | 80000.00 | 2018-11-05 |
| 5 | Tom Hardy | Marketing | 55000.00 | 2022-06-01 |
Explanation:
- The query uses the
WHEREclause to filter rows wheresalary > 50000. - The
SELECT *returns all columns from those filtered rows.
If you'd like to sort the result by salary or name, or only show name and salary, here are a few options:
Sort by Salary (Descending)
SELECT * FROM employees
WHERE salary > 50000
ORDER BY salary DESC;
Show only name and salary
SELECT name, salary FROM employees
WHERE salary > 50000;
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